(X^2+2x-5)-(3x+2)=x^2+1

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Solution for (X^2+2x-5)-(3x+2)=x^2+1 equation:



(X^2+2X-5)-(3X+2)=X^2+1
We move all terms to the left:
(X^2+2X-5)-(3X+2)-(X^2+1)=0
We get rid of parentheses
X^2-X^2+2X-3X-5-2-1=0
We add all the numbers together, and all the variables
-1X-8=0
We move all terms containing X to the left, all other terms to the right
-X=8
X=8/-1
X=-8

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